Master Advanced Physics
(For all Top Exams)
PROJECTILES - 2
Here the two motions are
Ucos (theta) in the horizontal direction
U sin(theta) in the vertical direction
UCos(theta) = R/T
0= USin(theta) - gT (v= u + at)
H = USin(theta) T + ½ gT2 (s= ut + ½ at2)
-U2 Sin2(theta) = 2 gH (v2 – u2 = 2as)
So,
Time taken to reach the Maximum Height=
T max = USin(theta) /g
( At H= Greatest height reached (theta is 90 and sin 90 = 1) )
H = u2 Sin2(theta) /2g = u2 /2g (sin(theta) = 1 )
Total time of flight = T = 2(USin(theta)) /g
Equation of trajectory
Y = x tan(theta) – gx2/2u2Cos2(theta)