June 05, 2020

PROJECTILES-2 (Master Advanced Physics)

Master Advanced Physics 
(For all Top Exams) 

PROJECTILES - 2 


Here the two motions are 

Ucos (theta) in the horizontal direction 

U sin(theta) in the vertical direction 


UCos(theta) = R/T 


0= USin(theta) - gT (v= u + at) 

H = USin(theta) T + ½ gT2 (s= ut + ½ at2) 

-U2 Sin2(theta) = 2 gH (v2 – u2 = 2as) 

So, 

Time taken to reach the Maximum Height= 

T max = USin(theta) /g 

( At H= Greatest height reached (theta is 90 and sin 90 = 1) ) 


H = u2 Sin2(theta) /2g = u2 /2g (sin(theta) = 1 ) 


Total time of flight = T = 2(USin(theta)) /g 


Equation of trajectory 

Y = x tan(theta) – gx2/2u2Cos2(theta)